
The C compiler identifies a function by its signature (function signature). The function signature is broken down into the following components in that order.
<return type>
<function label or name>
<parameters list>
The parameter list is further defined as <data type> parameter label or name. If the order of the parameters (datatype name) changes even if the function name/label does not change the signature is considered unique. So in C it is conceivable to have many different functions/methods with exact same label name (for example Function1) so long as the entire signature is considered unique. So changing the number of parameters their data types the order of them or any combination of these can change the function signature.
Important Note: Changing the return type ALONE is NOT considered change in signature.
Now answering the actual question of overloading function vs. operator:
Function Overloading: When you define many different functions (unique signatures) which have the exact label name it is function overloading. For example void Function_Foo();
void Function_Foo(int); // Overloaded
void Function_Foo(int int); // Overloaded
int Function_Foo(); // Error - function redefined (because only return type is different)
Operator Overloading: In C basic operators are also considered functions at a compiler level. So when you define a different operation for an operator by changing the standard parameter list it is operator overloading. For example
MyClass operator (MyClass& cls); //Add the data members of two instances of the same class
... etc.

Here are some examples
1) Function overloading
class FuncOver {
public:
// Constructors can also be overloaded.
FuncOver();
// Overloaded constructor.
FuncOver(int i);
// Functions example.
int sum(int a int b);
int sum(float a float b);
};
Operator overloading example...
class MyInt {
public:
// operator overloaded.
int operator (MyInt b);
private:
int a;
};
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